(5x^2-15)+x+(4x^2-2x)=180

Solution for (5x^2-15)+x+(4x^2-2x)=180 equation:

(5x^2-15)+x+(4x^2-2x)=180

We move all terms to the left:

(5x^2-15)+x+(4x^2-2x)-(180)=0

We add all the numbers together, and all the variables

x+(5x^2-15)+(4x^2-2x)-180=0

We get rid of parentheses

5x^2+4x^2+x-2x-15-180=0

We add all the numbers together, and all the variables

9x^2-1x-195=0

a = 9; b = -1; c = -195;
Δ = b2-4ac
Δ = -12-4·9·(-195)
Δ = 7021
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{7021}}{2*9}=\frac{1-\sqrt{7021}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{7021}}{2*9}=\frac{1+\sqrt{7021}}{18}
$